2[8x-(5x+2)-x]-2(2x-1)=1

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Solution for 2[8x-(5x+2)-x]-2(2x-1)=1 equation: 


Simplifying
2[8x + -1(5x + 2) + -1x] + -2(2x + -1) = 1

Reorder the terms:
2[8x + -1(2 + 5x) + -1x] + -2(2x + -1) = 1
2[8x + (2 * -1 + 5x * -1) + -1x] + -2(2x + -1) = 1
2[8x + (-2 + -5x) + -1x] + -2(2x + -1) = 1

Reorder the terms:
2[-2 + 8x + -5x + -1x] + -2(2x + -1) = 1

Combine like terms: 8x + -5x = 3x
2[-2 + 3x + -1x] + -2(2x + -1) = 1

Combine like terms: 3x + -1x = 2x
2[-2 + 2x] + -2(2x + -1) = 1
[-2 * 2 + 2x * 2] + -2(2x + -1) = 1
[-4 + 4x] + -2(2x + -1) = 1

Reorder the terms:
-4 + 4x + -2(-1 + 2x) = 1
-4 + 4x + (-1 * -2 + 2x * -2) = 1
-4 + 4x + (2 + -4x) = 1

Reorder the terms:
-4 + 2 + 4x + -4x = 1

Combine like terms: -4 + 2 = -2
-2 + 4x + -4x = 1

Combine like terms: 4x + -4x = 0
-2 + 0 = 1
-2 = 1

Solving
-2 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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